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Subject: Re: Log base 2From: Philipp Pertermann (philipp.pertermann_at_web.de)
Date: 2002-09-19
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From: "Jack Peel"
> But don't you want a log base 20 ? (or am I remebering dB
wrong ? )
> I should probably go do some research before I start
popping off :-)
In order to convert a linear volume sample info into dBfs I
have to calculate:
dBfs = 20 * log( sample / SAMPLE_RANGE)
with log being the logarithmus base 10.
Phil
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