Rockbox mail archive
Subject: Re: button?
From: Minuk Choi (Choi.Minuk_at_verizon.net)
well, so far, my idea is to solder wires on the 4 pins and have the
connection made by the button up top. I'm not too skilled in soldering...
and I want to avoid trying to remove the switches... and end up removing an
IC or something
----- Original Message -----
From: "Nathan" <nvpryor_at_comcast.net>
Sent: Monday, January 12, 2004 10:03 AM
Subject: RE: button?
> --| |--
> |_/ _|
> --| |--
> (ASCII push button switch)
> I believe the main purpose for having 4 leads (apart from being stronger),
is it allows you to make a matrix keypad on a single-sided PC board without
using alot of jumpers (since they're built into the switches) to hop over
the perpendicular traces. So two wires for each switch should be fine. A
better way is find the configuration of the switches and you may be able to
get away with only having either one wire per button plus a common, or the
horizontal and vertical lines of a matrix (total is usually twice the square
root of the button count).
> By the way if you're planning to remove the original switches from the
board be aware that it may either rely on the jumpers or may only have one
> >>>>>>begin origonal message snipit<<<<<<
> If you've seen the buttons on the circuit board, they look like the
> x1 x2
> x3 x4
> where "O" is the button itself, and x1, x2, x3, and x4 indicate soldered
> Now, from trial and error, it seems like x1 + x4 or x2 + x3 forms the
connection(i.e. button has been depressed). The thing is... is there a
reason that there are 4 points? Seems like 2 diagonal points is
sufficient(it works for power button, arrow buttons), but is there a reason
why it's four points?
> >>>>>>end origonal message snipit<<<<<<
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