BlueChip wrote:

> while (x>0) r = (r<<3)+(r<<1); // r*8 + r*2
> ^whoops
>
>
> At 19:52 06/07/2005, you wrote:
>
>> what values of 'x' ? all positive? include 0?
>>
>> if (x<0) return(0); // cannot handle negative values of x
>> if (x>9) return(-1); // result will be > (2^32)-1
>> unsigned long r = 1;
>> while (x>0) r = (r<<4)+(r<<1); // r*8 + r*2
>> return (r);
>

It might be a good idea to decrement x at some point too.... :)

> while (x>0) r = (r<<3)+(r<<1); // r*8 + r*2

perhaps:

    for (; x>0; --x) r = (r<<3)+(r<<1); // r*8 + r*2

~ray

-- 
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