Rockbox mail archiveSubject: Re: dB volume
Re: dB volume
From: Fred Maxwell <rockbox_at_anti-spam.org>
Date: Fri, 19 Mar 2004 15:08:31 -0500
Uwe Freese wrote:
> I would also prefer a dB display going from -something dB to 0dB.
So are you recommending that Rockbox report the +12dB point as 0dB? Or
did you want Rockbox changed so that the highest value of 0dB is what we
call 93% now?
I'm confused about all of this. A decibel is a logarithmic expression
of the ratio between two signal power, voltage, or current levels.
Assuming that P2 and P1 are power in watts, the decibel rating can be
dB = 10 log10 (P2 / P1)
I understand that the wattage can be measured at the headphone output,
but how is it measured internally?
Note: Decibels can be calculated in terms of the effective voltage if
the load impedance remains constant: dB = 20 log10 (V2 / V1). Since
the headphones vary wildly in impedence, that calculation is out the window.
> I don't think this is so unusual - all the modern amplifiers /
> receivers (including mine) show volume in dB.
While typical mid-fi consumer products do that, high-end audio
components and professional products generally do not:
Received on 2004-03-19